问一个利用4选1实现F(x,y,z)=xz+yz'的问题？

big_singman 发表于: 2006-5-26 23:54 来源: DICDER -- 博客专栏

给的答案是： x,y作为4选1的数据选择输入，四个数据输入端分别是z或者z的反相，0，1 我做的答案是：选择信号是1和Z 数据接X.Y,其他两个任意，我是通过化简四选一的布尔表达式得出的我是一个新手，请问这种问题应该怎么入手呢？

最新回复

5life at 2006-5-28 21:15:58: 正确答案没错呀。 x y out 1 1 1 1 0 z 0 1 z' 0 0 0
dexterchn at 2006-6-06 11:02:07: The correct answer assumes both z and z' are available. Your answer does not need z'. I think yours is better. Here is how I did. z=1, F=x z=0, F=y So you can use 2-to-1 mux to implement it (F = z ? x : y).
浪客公子禅心 at 2006-6-06 21:20:24: 文字文字 1 : to work out this subject,the only work you have to do is that you write out the Logic expression of the 4-to-1 selector: As we all know ,Logic expression of the 4-to-1 selector is that: F=A'B'a+AB'b+A'Bc+ABd (we assume that the four input datas are a,b,c,d,and selecting inputs are A and B,then output is F) Now,how to format F(x,y,z)=xz+yz'? we can solve it with many methods: 1:connect two of the selecting inputs to 1 and Z(Z'),meanwhile the two items to x,y; 2:connect two of the selecting inputs to 0 nd Z(Z'),meanwhile the two items to x,y. and so on. 2:We may observed that the format F(x,y,z)=xz+yz' is a 2-to-1 selector Logic expression(Z is the selector,and x as well as y is the data input).Then the very work we do is to use a 4-to-1 selector to make a 2-to-1 selector. the easiest method is just the main author gave.
kandy at 2006-6-15 16:35:30: 3楼的分析的好透彻啊！不错！
rvisk at 2006-6-19 16:45:20: 纯数学问题啊说e文这点我佩服的5体投地